Hello All,

In this class, we Learn the following topics:

- Introduce Fraction
- Simplify a Fraction using GCF
- Change two fractions to the common denominator using LCM

#### What is Fraction

One object can be divided into a number of equal parts, therefore, each part from this object can be called as a fraction.

Some ways are used to describe a fraction For example, one tenth of an object can be written as

- a common fraction 1/10
- a decimal 0.1
- a percentage 10%
We will learn about percentages and decimals later.

Now let us have a closer look at the common fraction:

1

**numerator**says how many parts in the fraction

**vinculum**= “divide by”

10**denominator**says how many equal parts in the whole object**Denominator**can NOT be 0. Do you understand Why?

#### Simplify a Fraction using GCF

Simplify a fraction is to reduce the fraction to as simple as possible. It means the numerator and denominator can be taken off common factor as much as possible till they don’t have any common factor. The process is similar like finding **GCF. **If we know GCF of numerator and denominator, the simplifying process is just one step.

For example, let’s simplify Fraction **6/12. **We can figure out the GCF for numerator 6 and denominator 12 is 6 (Please check the Ladder Method we learned in the last class). The

Numerator 6 ÷ GCF (6) = 1

Denominato 12 ÷ GCF (6) = 2

Then, fraction 6/12 can be simplified to 1/2; and also, 6/12 is **equivalent** to 1/2.

#### Change two fractions to the common denominator using LCM

When we are doing fractions’ comparison/addition/subtraction etc., we have to make fractions to be in a same denominator. The same denominator can be found via common multiple. If we use **Least Common Multiple (LCM)**, the process to find the same denominator will be simple.

for example, we are going to deal with 1/5 and 2/3,

### Homework:

Please check the parents’ email.

### The Plan for the next class:

Fractions’ Addition/Subtraction/Comparison/Ordering

We can see how the common denominator is used in the above calculation.

Thanks